c++ - Using numeric_limits to default parameter values -

i have template statistics class has range parameters.

template <typename t> class limitstats { public:     limitstats(t mx, t min) :       max(mx),       min(mn),       range(mx-mn)     {;}  private:     const t max;     const t min;     const t range; } 

i put default values of maximum , minimum allowable values, minimum value not same floating point , integer types.

normally can write

t min_val = numeric_limits<t>::isinteger ? numeric_limits<t>::min() : -numeric_limits<t>::max(); 

i have found can't use default parameter

limitstats(t mx = std::numeric_limts<t>::max(),             t mn = numeric_limits<t>::isinteger ? numeric_limits<t>::min() : -numeric_limits<t>::max()) 

is there way of achieving this?

you might want rethink design. trying limitstats std::numeric_limits doesn't provide?

don't replicate badness of design of std::numeric_limits. example, std::numeric_limits<double>::min() terribly misnamed. minimum double additive inverse of maximum double. std::numeric_limits abuse of notation , abuse of templates. in opinion, of course.

your idea min ill-formed. think default respect limitstats<unsigned int>.

with defaults, range invalid signed integers. unsigned ints replicates max, assuming fix problem limitstats<unsigned int>::min. floating point types, either invalid or replicates max, depending on mean limitstats<floating_point_type>::min.

does make sense allow default values? wouldn't have question if don't provide defaults , make default constructor private/unimplemented.