How to write a xquery in SQL Server to read all the childnodes from an XML data column in a table? -

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i have table in sql server named [queryresult] columns of type init, of type xml.

here sample xml of result column data.

<output> <item>     <value001>2023038.09</value001>     <value002>265127.97</value002>     <value003>459868.86</value003>     <value004>16000.01</value004>     <value005>552010.15</value005>     <value006>21404.96</value006> <item> <item>     <value001>15655501.89</value001>     <value002>17172.50</value002>     <value003>8345.31</value003>     <value004>-117264374.12</value004>     <value005>-160893.48</value005> </item> </output>

i need query returns output follows:

id      element          value ----------------------------------- 1   value001     2023038.09 2   value001    2023038.09 3   value002    265127.97 4   value003    459868.86 5   value004    16000.01 6   value005    552010.15  7   value006    21404.96 8   value001    15655501.89 9   value002    17172.50 10  value003    8345.31 11  value004    -117264374.12 12  value005    -160893.48

let me know if question not clear you?

here's 1 solution:

declare @xml xml =  ' <output> <item>     <value001>2023038.09</value001>     <value002>265127.97</value002>     <value003>459868.86</value003>     <value004>16000.01</value004>     <value005>552010.15</value005>     <value006>21404.96</value006> </item> <item>     <value001>15655501.89</value001>     <value002>17172.50</value002>     <value003>8345.31</value003>     <value004>-117264374.12</value004>     <value005>-160893.48</value005> </item> </output> '  select  t.c.value('local-name(.)[1]', 'varchar(100)') element,         t.c.value('./text()[1]', 'decimal(17,2)') value   @xml.nodes('//item/child::node()') t(c);

returning ordinal position of node more difficult looks. this question suggests 1 solution haven't implemented here it's bit of hack.


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