Python - Printing Hex from a file -

i have following code:

code1 = ("\xd9\xf6\xd9\x74\x24\xf4\x5f\x29\xc9\xbd\x69\xd1\xbb\x18\xb1") print code1  code2 = open("code.txt", 'rb').read() print code2 

code1 output:

�צ�t$פ_)�½i�»± 

code2 output:

"\xd9\xf6\xd9\x74\x24\xf4\x5f\x29\xc9\xbd\x69\xd1\xbb\x18\xb1" 

i need code2 (which read file) have same output code1.
how can solve ?

to interpret sequence of characters such as

in [125]: list(code2[:8]) out[125]: ['\\', 'x', 'd', '9', '\\', 'x', 'f', '6'] 

as python string escaped characters, such as

in [132]: list('\xd9\xf6') out[132]: ['\xd9', '\xf6'] 

use .decode('string_escape'):

in [122]: code2.decode('string_escape') out[122]: '\xd9\xf6\xd9t$\xf4_)\xc9\xbdi\xd1\xbb\x18\xb1' 

in python3, string_escape codec has been removed, equivalent becomes

import codecs codecs.escape_decode(code2)[0]